#173
Examples of how to code a palidrome check in C++.
Notes
Naïve Reversal
The most basic way of checking: reverse the string and then compare to the original. The std::swap function can be used to swap (reverse) all the characters in a string:
string reverse(string s) {
int n = s.size();
for (int i = 0; i < n / 2; ++i) swap(s[i], s[n - i - 1]);
return s;
}
Range Comparison
The std::equal function can be used to write a one-line palindrome check by comparing two iterators over the input string:
- one iterator starts at the begin of the string
- the other iterator starts at the rbegin (reverse-beginning) of the string
- the comparison stops when the first iterator reaches the end of the string.
So the following call will iterate through all characters and return true if palindromic:
equal(given.begin(), given.end(), given.rbegin())
This approach has the advantage of not creating any copies of the given string. It does suffer from checking all characters in the string, when it only needs to check to the halfway point.
Running the Example
See example.cpp for details. A makefile compiles and runs:
$ make
c++ -std=c++17 -g -Wall -O3 example.cpp -o example
./example
If you type in a word, I'll tell you if it is a palindrome.
abc33cba
Checking by explicitly reversing the string: Yes, abc33cba is a palindrome.
Checking with a range comparison: Yes, abc33cba is a palindrome.
$ make
./example
If you type in a word, I'll tell you if it is a palindrome.
abc
Checking by explicitly reversing the string: No, abc is not a palindrome.
Checking with a range comparison: No, abc is not a palindrome.
Credits and References
- std::swap
- std::equal
- std::begin - Returns an iterator to the beginning of the given range.
- std::rbegin - Returns an iterator to the reverse-beginning of the given range
- std::end